Form 2 Mathematics – EXPONENT AND RADICALS msomimaktaba, November 13, 2018August 17, 2024 EXPONENT AND RADICALS EXPONENTS:– Is the repeated product of real number by itselfe.g. i) 2 x 2 x 2 x 2 = 24ii) 6 x 6 x 6 x 6 x 6 = 65iii) a x a x a x a x a = a5LAWS OF EXPONENTS MULTIPLICATION RULESuppose; 4 x 4 x 4 = 43Then, 43 = power4 = base3 = exponentSuppose, 32 x 34 = 3(2+4) = 3632 x 34 = 3 x 3 x 3 x 3 x 3 x 3 = 36 Example 1 Simplify the followingi) 64 x 68 x 66 x 61ii) y4 x y0 x y3 Solution:i) 64 x 68 x 66 x 61 = 6 4+8+6+1= 619ii) y4 x y0 x y3Solution:Y4 x y0 x y3 = y4+0+3= y7Example 2 Simplify the followingi) 32 x 54 x 33 x 52ii) a3 x b3 x b4 x a5 x b2Solution:i) 32 x 54 x 33 x 52 = 32+3 x 54+2= 35 x 56ii) a3 x b3 x b4 x a5 x b2 = a3+5 x b3= a8 x b9Example 3If 2Y x 16 x 8Y = 256, find ySolution:2y x 24 x 8y = 2562y x 24 x 8y = 282y x 24 x (23)y = 28y + 4 + 3y = 8y + 3y = 8 – 44y = 4Y = 1Exercise 1:1. Simplifyi) 34 x 43 x 38 x 34 x 42 = 34+8+4 x 43+2 = 316 x 45ii) a2 x a3 x a4 x b2 x b3 = a2+3+4 x b2+3 = a9 x b52. If 125m x 252 = 510 find mSolution:125m x 252 = 51053m x 54 = 5103m + 4 = 103m = 10 – 43m=6m = 23. If x7 = 2187. Find xSolution:X7 = 2187 X7 = 37X = 3QUOTIENT LAW= = 3 X 3= 32Also = 34-2 = 32Generally: Example 1.Find i) = 87-5 = 82ii) = 52n-n = 5nExample 2.If = 81 find nSolution:= 81() = 3433n – 4 = 34Equate the exponents 3n – 4 = 4n= NEGATIVE EXPONENTSSuppose = 32 – 4 = 3-2Also = = and Inversely xn = ExampleFind( i) 2-3 = = (ii) 9-1/2 = (iii) = 33 = 27EXERCISE 2 1. Given 23n x 16 x 8n = 4096 find n2. Given = 56 find y3. If 32n+1 – 5 = 76 find n4. Given 2y = 0.0625.Find y 6. Find the value of x(i). 81-1/2 = xii) 2-x = 8ZERO EXPONENTSSuppose,= = 1 30 = 1 ExampleShow that 90 = 1Consider = = = 1Also = 92-2 = 9090 = 1 hence shownAlso(i) m = (ii) (x y)m = xm ym Example(1)Find i) (5 x 4)2Solution:(5 x 4)2 = 52 x 425 x 5 x 4 x 4 = 400ii) ()3= = 2. Show that 2-1 = Solution:2-1 = = consider LHS2-1 = L H S = R H STherefore2-1 = hence shownFRACTIONAL EXPONENTS AND EXPONENTS OF POWERSEXPONENTS OF POWERSConsider (54)3=(5x5x5x5)3 =(5x5x5x5)x(5x5x5x5)x(5x5x5x5) =5x5x5x5x5x5x5x5x5x5x5x5 =512 Similarly (54)3=54×3 Examples: 1.Simplify (a (x4)5(b) (86)3Solution (a) (x4)5=x4×5 =x20(b) (86)3= 86x3 =8182.Write 23x 42 as a power of single number Solution 23x 42 ,but 4=22therefore 42=(22)2 42=22×2 =24 23x 24=23+4 ∴23x 24=27 FRACTIONAL EXPONENT SolutionConsider the exponents of powers when is squared, we get Let x be positive number and let n be a natural number. Then Examples:(1) Find Thus if x is a negative number, and n is an odd numberExercise 2.1. Show that 2-2 = Solution:Consider LHS2-2 = = 2-2 = LHS = RHS hence shown2. Evaluate272/3 x 729 1/3 ÷ 243Solution:27 2/3 x 729 1/3 ÷ 243(33)2/3 x (36)1/3 ÷ 35 32 x 32 ÷ 3532+2-5= 3-1 or 3. Find the value of m(1/9)2m x (1/3)-m ÷ (1/27)2 = (1/3)-3m Solution:(1/32)2m x 1/3-m ÷ (1/33)2 = 1/3-3m(1/3)4m x (1/3)-m ÷ (1/3)6 = (1/3)3m3-4m x 3-m ÷ 3-6 = 3-3m-4m + -m – 6 = -3m-5m – 6 = -3m6 = -2mm = -34. Given 2x x 3y = 5184 find x and ySolution:2x = 5184 2x x 3y = 26 x 3y2x = 26 By comparison2x = 26 2x = 26X = 63y = 5184 3x = 343y = 34y = 4The value of x and y is 6 and 4 respectively RADICALS-A number involving roots is called a surd or radical. -Radical is a symbol used to indicate the square root, cube root or nth root of a number. -The symbol of a radical is Example of Radicals (i) (ii) (iii)PRIME FACTORSExample 1Find (i) by prime factorizationSolution: = = 2×7= 14ii) by prime factorizationsolution: = = 2 x 3= 6iii) by prime factorizationsolution: = = 2 Example 2If = 8x find xSolution: = = 8x= (23)1/3 = 23x= 21 = 23xx= Exercise 31. Find the followingi) Solution = = 2 x 2 x 2 x 2 x 2= 32 =32ii) Solution = = 52. Simplifya) Solution = = 5 b) == 3 x 5 = 15 3. Find = 16y find y = = 24y2 2 = 24y2 = 4yy = 4. Find x if =491/3Solution = = 491/33431/x = 73/x = (72)1/373/x = 7 2/3= 2x = 9x =ii) = 81xsolution== 81x = 32 = 34x= 2 = 4xx = OPERATION ON RADICALADDITIONExample1.Evaluatei) +3Solution: + 3=(1 + 3) =4ii) + Solution=+(22)1/2 (32)1/2 + (22)1/2 (22)1/2 = (2 x 3) + (2 x 2) = 6 + 4 = 10 SUBTRACTIONExampleEvaluatei) 3 – 2 Solution= 3 n-2= (3 x 2 x 3 2 x 2 x 2 )= 18 8 = 10 ii) Solution = =(2 x 3) (2 x 2) = 6 4= 2 MULTIPLICATIONExampleFind i) x solution x = = = = 2 x 2 x 2 x 3= 24ii) 3 x 3Solution3 x 3 (5 x 3) x (3 x 3) = 15 x 9 = 135 DIVISIONExample 1Find i) Solution: = = = = EXERCISE 4.1. Find 2 + 3 Solution: 2 +3 = (2 x 2 x 3)+ (3 x 2 x 2)= 12 +12 = 24 (ii )3 Solution:3 = 3 + 3 = 3 + 3 =(3 x 2) +(3 x 2 x 3) = 6 +12 = 18 (iii) 6 2 Solution:6 2 6 = 2 = (6 x 2) (2 x 3) = 12 6= 6 iv) + Solution: + +3 4 (v) + 2250Solution: + = +2250= 2 + 2250=2 + 2250=2 + 22502. Simplify(i) x = = = = 24ii) ()= (2 x 3 – 4 )= (6 – 4 )= (2 )= 4(iii) 3 x 2 Solution:= 3 x 2 = 3 x 2 x 3 x (2 x 2) = 18 x 4= 72 (iv) (15 )Solution:(15 )= 15 = 15 X 3= 45RATIONALIZATION OF THE DENOMINATOR– Rationalizing the denominator involves the multiplication of the denominator by a suitable radical resulting in a rationaldenominator. The best choice can follow the following rules:- (i) If a radical is a single term(that is does not involve + or -),the proper choice is the radical itself,that is (ii)If the radical involves operations(+ or -),choose a radical with the same format but with one term with the opposite operation.Examples The same technique can be used to rationalize the denominator.Example 1Rationalize i) Solution = x = (ii) Solution: = x = = (iii) Solution: = x = = = = Example 2:Rationalize (i) Solution: = x = = = = = = (ii) Rationalize Solution: = x = = = = = = = EXERCISE 5 1. Evaluate(i) ()()Solution: (1) ()() = (() -4()= – 6 – 12 + 12 (ii) ()()Solution: (iii) ()() = () + ()= a + + + b= a + b + 2(iv) ()()Solution:()() = () + ()= m + – – n= m – n(v) ()()Solution:()() = ( – ()= p – + – q= p – q2. Rationalize(i) Solution: = x = = = = = (ii) Solution:= = = – ( ) EXERCISE 6Rationalize the following denominator(i)Solution:= = = = (ii)Solution:= = = = (iii) Solution:= = = = (iv) Solution:= = = SQUARE ROOT OF A NUMBERExampleFind( i) Solution ii) Solution: (iii)Solution:TRANSPOSITION OF FORMULA A formula expresses a rule which can be used to calculate one quantity where others are given,when one of the given quantity is expressed in terms of the other quantity the process is called transposition of formula.Example 1The following are examples of a formulaa. A = b. v = c. I = d. A = (a +b)he. T = 2rExample 2The simple interest (I) on the principal (p) for time (T) years. Calculated at the rate of R% per annual is given by formulaI = Make T the subject of a formulaSolution:100 x I = x 100= = T = Example 3.Given thatY = mx + c, make m the subjectSolution:Y = mx +c = m = Example 4 Given that p = w Make a the subject.Solution:P = w Divide by w both sides= = Multiply by (1 – a) both sides(1 – a) = (1 a)(1 – a) = 1 + a– = 1 + a – 1 = a + – 1 = a(1 + )Divide by 1 + both sides= a = AlternativelyExample 5Given that T = 2 write g in terms of other lettersSolution:T = 2Divide by 2both side= Remove the radical by squares both sides2 = 2 = Multiply by g both sides =g= Multiply by 42 both sides42 x = x 42T2g = 42Divide by T2 both sides∴ g = Example 6If A = p + (i) Make R as the subject formula(ii) Make P as the subject formulaSolution:(i) A = p + = A – P = Multiply by 100 both sides= = R R = (ii) A = P + Solution:Multiply by 100 both sides100A = 100P + PRT100A = P(100 + RT)Divide by 100 + RT both sides= P P = Exercise 71. If S = at2. Make t the subject of the formula2. If c = (F – 32) make F the subject of the formulaSolution:S = at2Multiply by 2 both sidess x 2 = at2 x 22s = at2Divide by a both sides= t2 = Square root both sides= t = 2. C = (F – 32)C = F – C + = Multiply by 9 both sides9C + = Divide by 5 both sidesF = More Examples1. If A = (a + b)(i) Make h the subject formula(ii) Make b the subject formula2. If = – (i) Make f the subject formula(ii) Make u the subject formulaSolution:1. A = 2A = (a + b)x 22A = (a + b)Divide by a + b both sides= h = (ii) Make b the subject formula.Solution:A = 2A = (a + b)x 22A = (a + b)2A = ah + bh2A ah = bhDivide by h both sides = bb = 2. = – Solution:= – = Divide by u – v both sidesf = ii) Make u the subject formula= – Solution:= Multiply by uv both sides= f(u – v)uv = fu – fvfv = fu – uvfv =u (f – v)Divide by f – v both sidesu = Exercise 81. If T = (i) Make t the subject formula(ii) Make g the subject2. If P = w (i) Make w as the subject formula(ii) Make a the subject formulaSolution:1. (i)T = Square both sidesT2 = Multiply by 4 both sides4T2 = 4T2g = 9tDivide by 9 both sidest = (ii) Make g the subject formulaT = Solution:Square both sidesT2 = Multiply by 4 both sides4T2 = 4T2g = 9tDivide by 4T2 both sidesg = 2)( i) Make w was the subjectMake a the subjectSolution:P = w P= w()Divide by () both sidesw =P ii) Make a the subject formulaSolution:P = w Divide by w both sides= = Multiply by (1 – a) both sides(1 – a) = (1 a)(1 – a) = 1 + a – = 1 + a – 1 = a + – 1 = a(1 + )Divide by 1 + both sides= a = Exercise 9I. If v = Make R the subject formulaSolution:v = Multiply by r + R both sidesv (r + R) = 24Rvr + Rv = 24 Rvr = 24R – Rvvr = R (24 – v)Divide by 24 – v both sides2. If m = n (i) Make x the subject formulaSolution:m = n Multiply by x + y both sidesmx + my = nx – nymy + ny = nx – mxmy + ny = x(n – m)divide by n – m both sidesx = (ii)If T = 2Make t the subject formulaSolution:T = 2Square both sidesT2 = 42Multiply by a both sidesT2a = 42ktDivide by 42k both sidest = 2 ALL NOTES FOR ALL SUBJECTS QUICK LINKS:AGRICULTURE O LEVEL PURE MATHEMATICS A LEVELBAM NOTES A LEVELBASIC MATH O LEVELBIOLOGY O/A LEVELBOOK KEEPING O LEVELCHEMISTRY O/A LEVELCIVICS O LEVELCOMPUTER(ICT) O/A LEVELECONOMICS A LEVELENGLISH O/A LEVELCOMMERCE O/A LEVELACCOUNTING A LEVELGENERAL STUDIES NOTESGEOGRAPGY O/A LEVELHISTORY O/A LEVELKISWAHILI O/A LEVELPHYSICS O/A LEVELMOCK EXAMINATION PAPERSNECTA PAST PAPERS Basic Mathematics Study Notes Form 2 Basic Mathematics Study Notes Msomi Maktaba All Notes FORM 2MATHEMATICSPost navigationPrevious postNext postRelated Posts Form Six Past Papers Chemistry Form Six Past Papers – NECTA A Level October 16, 2019October 16, 2019Click The Links Below to download Form 6 Past Papers Chemistry Year Questions/Answers 2019 Paper 1, Paper 2, Practical 3A 2018 Paper 1, Paper 2, Practical 3A, Practical 3B 2017 Paper 1, Paper 2, Practical 3A, Practical 3B 2016 Paper 1, Paper 2, Practical 3A, Practical 3C 2015 Paper 1,… Read More KCMC selected applicants 2024/24 | Kilimanjaro Christian Medical College selected applicants 2024 February 3, 2024KCMC Selected applicants 2023/2024 pdf: Have you applied for Diploma, certificate or bachelor degree admission at Kilimanjaro Christian Medical College for 2023/2024 academic year and you have been anxiously waiting to see if you have been selected to join KCMC and you don’t know how and where to get your… Read More KIUT Selected applicants 2023/2024 pdf February 3, 2024KIUT Selected applicants 2023/2024 pdf: Have you applied for Diploma, certificate or bachelor degree admission at Kampala International University in Tanzania for 2023/2024 academic year and you have been anxiously waiting to see if you have been selected to join KIUT and you don’t know how and where to get… Read More Leave a Reply Cancel replyYour email address will not be published. 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Form Six Past Papers Chemistry Form Six Past Papers – NECTA A Level October 16, 2019October 16, 2019Click The Links Below to download Form 6 Past Papers Chemistry Year Questions/Answers 2019 Paper 1, Paper 2, Practical 3A 2018 Paper 1, Paper 2, Practical 3A, Practical 3B 2017 Paper 1, Paper 2, Practical 3A, Practical 3B 2016 Paper 1, Paper 2, Practical 3A, Practical 3C 2015 Paper 1,… Read More
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KIUT Selected applicants 2023/2024 pdf February 3, 2024KIUT Selected applicants 2023/2024 pdf: Have you applied for Diploma, certificate or bachelor degree admission at Kampala International University in Tanzania for 2023/2024 academic year and you have been anxiously waiting to see if you have been selected to join KIUT and you don’t know how and where to get… Read More